SQL Server Join Example. SQL Server LEFT OUTER JOIN Example. It looks like Microsoft has changed the AdventureWorks database and this query no.

I'm converting from SQL Server 2000 to SQL Server 2012. I've encountered either a bug or syntax that I don't understand. I've created a T-SQL example to illustrate the issue. Consider the T-SQL below. Since I'm performing a LEFT OUTER JOIN, why don't all cars appear in the result set. My contention is that I should see a result row containing car_id=1, driver_id=NULL and driver_name=NULL. Any insight would be appreciated.

Your statement is correct but the data is incorrect. How can you get the result when you don't have the Car with car_id=1. The select statement will get all the values from the car table and the selected (matched) values from the Driver table. SELECT car_id AS 'Car', c.driver_id AS 'Driver', driver_name AS 'Name' FROM car c LEFT OUTER JOIN driver d ON c.driver_id = d.driver_id ORDER BY car_id, c.driver_id Insert the Car with car_id=1 in your table and you will get the result you want. Hope this helps, Thanks, Parth. Chuck: The issue is that I do not see car_id=1 in the result set.

My contention is the the result set should have 4 lines. One line should contain car_id=1 with the other values NULL. Three lines should contain car_id=2. Spotify Premium Cracked Version Android Apk. The result set returned shows only the 3 lines with car_id=2. Wayne Baxter You don't have any records where carid = 1 carid = 2 in all 3 records you inserted --Load car table INSERT INTO car (car_id, driver_id) VALUES (2,1) INSERT INTO car (car_id, driver_id) VALUES (2,2) INSERT INTO car (car_id, driver_id) VALUES (2,3) go Chuck. Naomi: I want all cars, not all drivers.

The OUTER JOIN does not return car_id=1. To All: My apologies. Stubbs The Zombie Xbox Iso Torrent on this page. I have a complicated query that is failing. I tried to construct a simple example to illustrate the problem.

I made a mistake in constructing the example. The correctly constructed example appears below and returns the result set that I expect. I have to reanalyze my complicated query.

I'm converting from SQL Server 2000 to SQL Server 2012. I've encountered either a bug or syntax that I don't understand. I've created a T-SQL example to illustrate the issue.

Consider the T-SQL below. Since I'm performing a LEFT OUTER JOIN, why don't all cars appear in the result set. My contention is that I should see a result row containing car_id=1, driver_id=NULL and driver_name=NULL.

Any insight would be appreciated. Your statement is correct but the data is incorrect. How can you get the result when you don't have the Car with car_id=1. Arhitektonsko Projektovanje Pdf. The select statement will get all the values from the car table and the selected (matched) values from the Driver table.

SELECT car_id AS 'Car', c.driver_id AS 'Driver', driver_name AS 'Name' FROM car c LEFT OUTER JOIN driver d ON c.driver_id = d.driver_id ORDER BY car_id, c.driver_id Insert the Car with car_id=1 in your table and you will get the result you want. Hope this helps, Thanks, Parth. Chuck: The issue is that I do not see car_id=1 in the result set. My contention is the the result set should have 4 lines. One line should contain car_id=1 with the other values NULL. Three lines should contain car_id=2.

The result set returned shows only the 3 lines with car_id=2. Wayne Baxter You don't have any records where carid = 1 carid = 2 in all 3 records you inserted --Load car table INSERT INTO car (car_id, driver_id) VALUES (2,1) INSERT INTO car (car_id, driver_id) VALUES (2,2) INSERT INTO car (car_id, driver_id) VALUES (2,3) go Chuck. Naomi: I want all cars, not all drivers. The OUTER JOIN does not return car_id=1.

To All: My apologies. I have a complicated query that is failing. I tried to construct a simple example to illustrate the problem. I made a mistake in constructing the example. The correctly constructed example appears below and returns the result set that I expect. I have to reanalyze my complicated query.